(Latest Revision: 
Dec 1, 2022)  
Solution to the 2023 Flow Network Problem
For this problem, the A-side of the minimum cut is {s, b, c, d}.  No other nodes are reachable from the source, s, in the final version of the residual graph, Gf. The value of the max flow, v(f*), is the sum of the flows on the edges leaving the source node s in G.  That sum is v(f*) = 2 + 5 + 7 = 14.  The capacity of the min cut is the sum of the capacities of the edges (in G) leaving the A-side of the cut, 2 + 1 + 5 + 6 = 14 = v(f*).  These calculations verify that the max value of an s-t flow is equal to the  min capacity of an s-t cut, which, according to the "Max-Flow, Min-Cut Theorem," is true for any flow network.